If the point A(a,2) is equidistant from the points B(8,-2)
and C(2,-2), find the value of a.
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Answer:
Using distance formula
AB
2
=AC
2
⇒(a−8)
2
+(2+2)
2
=(a−2)
2
+(2+2)
2
⇒a
2
−16a+64+16=a
2
−4a+4+16
⇒−16a+64=−4a+4
⇒−16a+4a=4−64
⇒−12a=−60
⇒a=5
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