If the point A(x, y) is equidistant from P(a, b) and Q(−b, −a), then find the relation
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Answer:
Step-by-step explanation:
(x-a)²+y-b)²=(x+b)²+(y+a)²
x²+y²+a²+b²-2ax-2by=x²+y²+a²+b²--
+2bx+2ay
-2ax-2by=+2bx+2ay
2x(a+b)+2y(a+b)=0
x+y=0
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