if the point C(-1‚2) divides internally the line segment joining the points A(2‚5) and B(x‚y) in the ratio 3:4 find the value of x2+y^²
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Answer:
We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n is
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Since, C divides A & B in the ratio 3:4 internally
By section formula
3+4
3x+4(2)
=−1,
3+4
3y+4(5)
=2
⇒3x+8=−7, 3y+20=14
x=
3
−15
, 3y=−6
⇒x=−5, y=−2
x
2
+y
2
=(−5)
2
+(−2)
2
=25+4
∴x
2
+y
2
=29.
Step-by-step explanation:
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