Question

If the point (h, k) is equidistant from the points (2, 0) and (0, 2), prove that h=k. [ 2 ]​

Answer 1

Answer:

y=0

Step-by-step explanation:

locus of point be P(h,k)

so A(0,2) & B(0,−2)

AP=(0−h)2+(k−2)2

BP=(0−h)2+(k+2)2

AP=BP (points are equidistant)

(0−h)2+(k−2)2=(0−h)2+(k+2)2

k2+4−4h=k2+4+4k

8k=0

k=0

put k=y

∴y=0

Answer 2

Step-by-step explanation:

(0−h)²+(k−2)²=(0−h)² +(k+2)²

k²+4−4h=k²+4+4k

8k=0

k=0

put k=y

∴y=0