Question

If the point (K +2,2k-3) lies on the graph of the equation 2 X +3y+15=0 find the value of k

Answer 1

Answer:

k = -5/4

Step-by-step explanation:

(k+2,2k-3) lies on the graph of the equation 2x + 3y + 15 = 0

So put x = k+2 and y= 2k-3 in the equation

2(k+2) + 3(2k - 3) + 15 = 10

2k + 4 + 6k - 9 + 15 = 0

8k + 10 = 0

8k = -10

k = -10/8 = -5/4