Question

If the point (k,2) lies on the graph of the linear equation 4x-6y+16=0 ,then the value of k=?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given equation of line is 4x−6y+16=0⋯(1)

Also given that (k,2) lies on the line

So (k,2) must satisfy the equation (1)

⟹4(k)−6(2)+16=0

⟹4k−12+16=0

⟹4a=−2

⟹a= -2

The value of a is -2