If the point (k,-3) lies on the graph of the linear equation 3y = 2x - 1 then find the value of k.
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(k, - 3)
3y-2x+1=0
3(-3)+2(k) +1=0
-9-2k +1=0
-2k=-1-9
-2k=-10
Minus cancel
K=5
3y-2x+1=0
3(-3)+2(k) +1=0
-9-2k +1=0
-2k=-1-9
-2k=-10
Minus cancel
K=5
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