Question

if the point (k,O) is equidistance from the point (7,6) (-3,4) and the value of x​

Answer 1

Step-by-step explanation:

Why is it important to make the right choices in life?

"It is so important to understand that we are all making choices all the time, even when we chose not to choose we have still made a choice. It is our choices that determine our experiences. ... Unless we are willing to take full responsibility for ourselves and the choices we make, we have no control over our lives.

Answer 2

Answer: k=3

Step-by-step explanation:

Let P(k,0),A(7,6) and B(-3,4)

Since point (k,0) is equidistant from the two pointa A and B.

AP=

$\sqrt{ {(k - 7)}^{2} + {(0 - 6)}^{2} }$

$\sqrt{ {k}^{2} - 14k + 49 + 36 }$

$\sqrt{ {k}^{2} - 14k + 85 }$

BP=

$\sqrt{ {(k - (- 3))}^{2} + {(0 - 4)}^{2} }$

$\sqrt{ {(k + 3)}^{2} + {4}^{2} }$

$\sqrt{ {k}^{2} + 6k + 9 + 16 }$

$\sqrt{ {k}^{2} + 6k + 25 }$

Ap=Bp

$\sqrt{ {k}^{2} - 14k + 85} = \sqrt{ {k}^{2} + 6k + 25}$

Squaring both sides

k^2-14k+85=k^2+6k+25

-14k-6k=25-85

-20k=-60

k=-60/-20=3

Thus, the value of k i.e the x-coordinate is 3

and the point P is (3,0)