if the point of intersection of kx+4y+2=0,x-3y+5=0 lies on 2x+7y-3=0 then k=
Answers
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-3
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-3
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equation
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0k(-2)+4(1)+2=0
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0k(-2)+4(1)+2=0-2k+4+2=0
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0k(-2)+4(1)+2=0-2k+4+2=02k=6
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0k(-2)+4(1)+2=0-2k+4+2=02k=6k=3
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0k(-2)+4(1)+2=0-2k+4+2=02k=6k=3Hope you understood !
If the point of intersection lies on all three lines, we simply have to solve the simultaneous equatioms.2(x-3y+5)=0=2x+7y-32x-6y+10=2x+7y-310+3=7y+6y13y=13y=1Putting its value in x-3y+5=0x-3(1)+5=0x-3+5=0x=-2Putting value of x and y in first equationkx+4y+2=0k(-2)+4(1)+2=0-2k+4+2=02k=6k=3Hope you understood !Sayonara !