if the point of p(x,y) is equidistant from the point A (6,1) and B(1,6) find the relation between x and y
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Step-by-step explanation:
PA=PB
or PA² = PB²
(6 − x)² + (−1 − y)² = (2 − x)² + (3 − y)²
(36 + x² − 12x) + (1 + y² + 2y) = (4 + x² − -
4x+9+ y² - 6y)
37 - 12x + 2y = 13 — 4x - 6y
8x = 8y +24
x - y = 3
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