Math, asked by rajaramarya1971, 10 months ago

If the point on the graph of the linear
equation 2x + 4y = 8, whose ordinate is 1.5
times, its abscissa, is
(1){3/2,1}(2) 1,{3/2}(3){-1,3/2)}(4) {1,-3/2}​

Answers

Answered by pankajyadavsapla
0

Answer:

Step-by-step explanation:

The correct answer is (2) option

Answered by GulabLachman
13

The point is : (2) 1,{3/2}

If a point is represented as (x,y), then x is called the abcissa and y is called the ordinate of the point.

It is given that the ordinate is 1.5 times the abcissa.

Let us comsider the abcissa to be 'x'.

According to the given relation the ordinate 'y' = 1.5x

So, the point stands as (x,1.5x)

If a point is situated on a particular line, then that point must satisfy the given equation of line.

Given line is : 2x + 4y = 8

Putting x = x, and y = 1.5x, we get:

2x + 4(1.5x) = 8

⇒ 8x = 8

⇒ x = 8/8 = 1

So, y = 1.5x = 1.5 = 3/2

Thus the point = (x,y) = (1, 3/2)

Option (2) is correct.

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