If the point P (-1,2) lies on the graph of the equation kx + 3y = 7. find the value of k
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Answer:
The value of k is - 1
Given : The point (-1,2) lies on the graph of the linear equation kx+3y=7
To find : The value of k ?
Solution :
If the point (-1,2) lies on the linear equation
K(-1)+3(2)=7
-k+6=7
Therefore, the value of k is - 1
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