Question

If the point P (2,2) is equidistant from the points A (-2, k) and B (-2k, -3), find k. Also, find the length of AP.

Answer 1

Here ,
PA = PB

PA^2 = PB^2
(2+2)^2 + (2-K)^2 = (2+2k)^2 + (2+3)^2
K^2+4K+3 = 0
(K+3) (K+1) = 0

HENCE ,

K= -1 , K = -3


$BE BRAINLY$

Answer 2

HEY BUDDY HERE IS UR ANSWER !!

PA = PB
PA^2 = PB^2
(2+2)^2 + (2-K)^2 = (2+2K)^2 + (2+3)^2
K^2 + 4K + 3 = 0
(K+3)(K+1) = 0
K= -3 or K = -1


HOPE U LIKE THE PROCESS !!

》》 BE BRAINLY 《《