Question

If the point p(2,-3) and q(10,y) having distance 10 units find y

Answer 1

By applying distance formula :

distance = √ (X2-X1)²+(Y2-Y1)²

10 = √ (10-2)²+(y-(-3))²

100=(8)²+(y+3)²

100-64= y²+9+6y

y²+6y-27=0 --------- eq(1)

y²+9y-3y-27

y(y+9) -3(y+9)

(y-3) (y+9)

y= 3 or y= -9