if the point p (3,4) lies on the line 3y-ax-7=0 . find the a
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Answer:
a=5÷3
Step-by-step explanation:
given point p(3,4)
line 3y-ax-7=0
the point p(3,4) lies on the line then
the line should passes through the point p(3,4)
=3(4)-a(3)-7
=12-3a-7
=5-3a
3a=5
a=5÷3
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