if the point P(a,-11),Q(15,b),R(2,15)and S(1,1)are the vertices of parallelogram.find the value of a and b
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1
We know that diagonals of a parallelogram bisect each other
X = a+2/2 .......1
Y = -11+15/2=4/2......2
Also
X=1+15/2=16/2.....3
Y=1+b/2......4
From equation 1 & 3
a+2/2=16/2
a=14
From equation 2 & 4
4/2=1+b/2
b=3
X = a+2/2 .......1
Y = -11+15/2=4/2......2
Also
X=1+15/2=16/2.....3
Y=1+b/2......4
From equation 1 & 3
a+2/2=16/2
a=14
From equation 2 & 4
4/2=1+b/2
b=3
Answered by
1
Answer:
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other
So the coordinates of the mid – point of the PR = Coordinates of the mid – point of the QS
{(2 + a)/2,(15 – 11)/2} = {(5 + 1)/2,(b + 1)/2}
2 + a = 6
a = 4
15 – 11 = b + 1
4 = b + 1
b = 3
Hence, a = 4, b = 3
Thanks!!!!
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