Question

If the point P(k, 0) divides the line segment joining the points A(2,-2) and
B(-7,4) in the ratio 1:2, then the value of k is
(a) 1
(b) 2
(c) -2
(d)-1​

Answer 1

Answer:-2

Step-by-step explanation:

Answer 2

The value of k is -1

Step-by-step explanation:

Given : P(k,0) divides the line segment joining the points A(2,-2) and B(-7,4) in ratio 1:2

To find: The value of k

Let $A(2,-2)= (x_1,y_1) \text { , } B(-7,4)= (x_2,y_2) \text { and } P(k.0)=(x,y)$

Also $m_1:m_2=1:2$

Now as by section formula we know that

$(x,y)=(\dfrac{x_1m_2+x_2m_1}{m_1+m_2} ,\dfrac{y_1m_2+y_2m_1}{m_1+m_2} )$

Now

$x= \dfrac{x_1m_2+x_2m_1}{m_1+m_2} \\\\\Rightarrow k= \dfrac{(2) \times 2+(-7)\times 1}{1+2} \\\\\Rightarrow k=\dfrac{4-7}{3} =\dfrac{-3}{3} = -1$

Therefore the value of k is -1

#Learn more

Find the ratio in which the point (2,x) divides the line segment joining the points A(-2,2) B (3,7) internally .Also find value of x​

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