Question

if the point p ( k - 1 , 2 ) is equidistant from the point A ( 3 , K ) and B ( k , 5 ) find the value of K​

Answer 1

Answer:

we have,

AP=BP

So by distance formula we have,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AP

2

=BP

2

(

(k−1−3)

2

+(2−k)

2

)

2

=(

(k−1−k)

2

+(2−5)

2

)

2

(k−4)

2

+(2−k)

2

=1+9

k

2

+16−8k+4+k

2

−4k=10

2k

2

−12k+20=10

k

2

−6k+5=0

(k−5)(k−1)=0

k=1,5

Mark me brainlist and follow