Question

if the point p(k-12) is equidistant from A(3,k) B(k,5) find the value of k​

Answer 1

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Answer 2

Solution :-

We have, AP = BP

So by distance formula

Distance In points = (x₂- x₁)² + (y₂- y₁)²

AP² - BP²

➼ (k - 4)² + (2 - k)²

➼ 1 + 9k² + 16 - 8k + 4 + k² - 4k = 10

➼ 2k² - 12k + 20 = 10

➼ k² - 6k + 5 = 0

➼ (k - 5) (k - 1) = 0

k = 1 , 5