Question

If the point P (x, 3) is equidistant from the points A (7,-1) and B (6, 8), find the value of x and find the distance AP.

Answer 1

Answer:

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Given,PA=PB(PA) 2 = (PB) 2

So by distance formula we have,Distance between two points = (x 2 −x 1 ) 2 +(y 2 −y 1 ) 2

⇒ (x−7) 2 +(3+1) 2 = (x−6) 2 +(3−8) 2 ⇒ x 2 +49−14x+16 = x 2 +36−12x+25⇒ 49+16−36−25=2x⇒ 65−61=2x⇒ x=4Distance:AP= (4−7) 2 +(−1−3) 2

(by distance formula)= (3) 2 +16 = 9+16 = 2 5=5

Answer 2

Answer:

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