Question

if the point p(x y) is equidistant from L (5,1)and M (-1,5) then find relation between x LY​

Answer 1

Step-by-step explanation:

Given, pl=pm(equidistant)

          squaring on both sides

           (pl)^2=(pm)^2

(x-5)^2+(y-1)^2=(-1-x)^2+(5-y)^2

x2+25-10x+y2+1-2y=1+x2+2x+25+y2-10y

                      12x-8y=0

                      3x-2y=0

The relationship between x and y is 3x-2y=0.

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