if the point p(x y) is equidistant from L (5,1)and M (-1,5) then find relation between x LY
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Step-by-step explanation:
Given, pl=pm(equidistant)
squaring on both sides
(pl)^2=(pm)^2
(x-5)^2+(y-1)^2=(-1-x)^2+(5-y)^2
x2+25-10x+y2+1-2y=1+x2+2x+25+y2-10y
12x-8y=0
3x-2y=0
The relationship between x and y is 3x-2y=0.
please try to solve yourself because my answer almost right
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