Question

If the point (x, 4) lies on a circle whose centre is at the origin and radius is 5 cm, then the value of x will be?
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Answer 1

Answer:

x = ±3

Step-by-step explanation:

point A = (0,0)

point B = (x, 4)

distance = 5

Using distance formula

$\sqrt{x^{2} + 4^{2} } = 5\\ x^{2} + 16 = 5^2\\x^{2} = 25-16\\x^{2} = 9\\\sqrt{x^{2}} = \sqrt{9} \\x = +3 . . . Or.... x=-3$

x = ±3