Question

If the pointA(2, -4)is equidisant from p(3,8)andQ(-10,y)find the value of y.also find distance pQ.

Answer 1

$\sqrt{ {(3 - 2)}^{2} + {(8 + 4)}^{2} } = \sqrt{ {( - 10 - 2)}^{2} + {(y + 4)}^{2} } \\ \sqrt{1 + 144} = \sqrt{144 + {y}^{2} + 16 + 8y } \\ 145 = 160 + {y}^{2} + 8y \\ {y}^{2} + 8y + 15 = 0 \\ (y + 3)(y + 5) = 0 \\ y = - 3 \\ y = - 5$