If the points (1,2),(-5, 6) and (p,- 2) are collinear, then p=
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line equation is
y-2 = [(6-2)/(-5-1)] × (x-1)
=> y - 2 = (4/-6) × (x-1)
=> y-2 = -2/3 × (x-1)
=> 3y - 6 = -2x + 2
=> 3y + 2x - 8 = 0
since (1,2),(-5, 6) and (p,- 2) are collinear, (p,-2) isa point on above line equation
=> x = p, y = -2
=> 3(-2) + 2(p) - 8 = 0
=> -3 + p - 4 = 0
=> p = 7
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