Question

If the points (2, 1) and (1,-2) are equidistant from the point (x, y), show that x + 3y = 0.

Answer 1

Answer:

LET SEE ..........SAGAR VERMA..........IS HERE

Step-by-step explanation:

VERY IS QUESTION FOR TODAY .,...,......,.

Answer 2

Let the given point be P(x,y) Q(2,1) and R(1,-2)

A/q

PQ=PR

→√(2-x)^2+(1-y)^2=√(1-x)^2+(-2-y)^2

→(2-x)^2+(1-y)^2=(1-x)^2+(-2-y)^2

→4+x^2-4x+1+y^2-2y=1+x^2-2x+4+y^2+4y

→-4x+2x-2y-4y=0

→-2x-6y=0

→x+3y=0

Hence, Proved