Question

if the points (2,1) and (1,-2)are equidistant from the point (x,y) show that x+3y=0​

Answer 1

Answer:

The distances of the point (2,1) and (1,−2) from (x,y) are (x−2)2+(y−1)2 and (x−1)2+(y+2)2 units respectively.

According to the problem,

(x−2)2+(y−1)2=(x−1)2+(y+2)2 

or, (x−2)2+(y−1)2=(x−1)2+(y+2)2

or, −4x+4−2y+1=−2x+1+4y+4

or, 2x+6y=0

or, x+3y=0.