If the points ( ,2−2 ) , ( − +1 ,2 ) and ( −4− ,6−2 ) are collinear, find the value of ‘a ‘.
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Answer:
Given points A(−2,−5),B(2,−2),C(8,a) are collinear
Hence area of triangle formed by A,B,C is zero
Area=
2
1
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0=
2
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−2
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8
−5
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a
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0=−2(−2−a)+5(2−8)+1(2a+16)
4+2a−30+2a+16=0
4a=10⇒a=
2
5
Step-by-step explanation:
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