if the points (2/5,1/3),(1/5,k)and(4/5,0) are collinear then find the value of k.
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Answer:
When three points A, B and C are collinear, slope of line
joining any two points (say AB) = slope of line joining any other two
points (say BC).
Slope of the line passing through points (x
1
,y
1
) and (x
2
,y
2
) =
x
2
−x
1
y
2
−y
1
Slope of the line passing through (
5
2
,
3
1
) and (
2
1
,k)= Slope of line passing through (
2
1
,k) and (
5
4
,0)
2
1
−
5
2
k−
3
1
=
5
4
−
2
1
0−k
On solving, k=
4
1
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