Question

If the points (2k-3, k+2) lies on the graph of the equation 2x+3y+15=0, find values of k.

Answer 1

Put 2k-3 as x and k+2 as y in the equation.

2(2k-3)+3(k+2)+15=0

4k-6+3k+6+15=0

7k=-15

k=-15/7

Hope its helpful.

Answer 2

2k - 3 = x ; k + 2 = y
2x + 3y + 15 = 0
Putting value of x and y from above
2(2k - 3) + 3(k + 2) + 15 = 0
4k - 6 + 3k + 6 + 15 = 0
7k + 15 = 0
7k = -15
k = -15 / 7