Question

if the points (3,_1),(p,0)and(1,_2)are collinear,then find the value of 'p'​

Answer 1

Answer:

Step-by-step explanation:

If the given points are collinear, the area of the triangle formed would be zero.

So, by the formula for area of a triangle=  1/2{x1(y2-y3) + x2(y3-y1) +x3(y1-y2) } = 0

Where,

x1=3                          y1= -1

x2=p                         y2= 0

x3=1                          y3= -2

Putting all the values,

0 =  1/2{ 3(0+2) + p( -2+1) + 1( -1-0) }

0=   1/2 { 3*2 + p( -1) - 1}

0=   1/2 { 6 - p - 1}

0=   1/2 {  5 - p}

0= 5 - p

Therefore, p=5 is your answer.

Thank you. Hope  you understood.