If the points (3, 2), (6, 3), (x,y ) & (6, 5) are joined in order and form a parallelogram then find (x,y).
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(9,6)
Let A, B, C, D be the point (3, 2) (6, 3)(x, y) and (6,5) respectively.
Since ABCD is a parallelogram, the diagonals AC and BD must bisect earth other i.e., the mid points of AC and the mid point of BD must coincide and hence the coordinates of the two mid points are the same
3+x 6+6 = 2 2 and 2+y 2 or 3 + x = 12and2 + y = 8 3+5 2 =
or x = 9andy = 6
Hence (x, y) = (9,6)
AB = (3− 1)² + (4 + 2)² = √40
BC = √(4 − 3)² + (7 − 4)² = 10 AC = √(4-1)² + (7+2)² : √90
..AABC is neither right angled nor equilateral triangle.
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