Question

If the points ( 5, 4) lies on the graph of the equation 3y = ax + 7, then find the value of ' a'. *

Answer 1

ANSWER

if the point (5,4) lies on the given line, x=3 and y=4 will satisfy the given equation.

,4) lies on the given line, x=3 and y=4 will satisfy the given equation.3y= ax+7

,4) lies on the given line, x=3 and y=4 will satisfy the given equation.3y= ax+73(4)= a(3)+7

,4) lies on the given line, x=3 and y=4 will satisfy the given equation.3y= ax+73(4)= a(3)+712 = 3a+7

,4) lies on the given line, x=3 and y=4 will satisfy the given equation.3y= ax+73(4)= a(3)+712 = 3a+712-7 = 3a

,4) lies on the given line, x=3 and y=4 will satisfy the given equation.3y= ax+73(4)= a(3)+712 = 3a+712-7 = 3a5= 3a

,4) lies on the given line, x=3 and y=4 will satisfy the given equation.3y= ax+73(4)= a(3)+712 = 3a+712-7 = 3a5= 3a5/3 = a

hope this helps you!

mark as brainliest answer.

Answer 2

Answer:

Q.A ans. Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.

Now, put x = 3 and y = 4 in given equation, we get

3(4) = a (3)+7

⇒ 12 = 3a+7

⇒ 3a = 12 – 7

⇒ 3a = 5

Hence, the value of a is 5/3.