Question

If the points (7,-2),(5,1)&(3,k) are collinear find the value of K

Answer 1

$7(1 - k) + 5(k + 2) + 3( - 2 - 1) = 0 \\ 7 - 7k + 5k + 10 - 9 = 0 \\ 8 - 2k = 0 \\ k = 4 \\ hope \: this \: helps \: u \: please \: mark \: brainliest$

Answer 2

Answer:

Step-by-step explanation:

1/2 |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)| = 0

1/2|7(1-k)+5(k+2)+3(-2-1)| = 0

7-7k+5k+10-9=0

8-2k=0

K= -8/-2

K=4