if the points (a,0),(0,b),(1,1) are collinear then show that 1÷a+1÷b=1
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slope of line joining (a,0), (0,b)=slope of (0,b), (1,1)
(b-0)÷(0-a)=(1-b)÷(1-0)
b÷-a=1-b
b÷(b-1)=a
(b-1)÷b=1÷a
1-1÷b=1÷a
1=1÷a+1÷b
(b-0)÷(0-a)=(1-b)÷(1-0)
b÷-a=1-b
b÷(b-1)=a
(b-1)÷b=1÷a
1-1÷b=1÷a
1=1÷a+1÷b
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