if the points (a, 0), (0, b) and (1, 1) a r e collinear, then prove that 1/a + 1/b=1
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Explanation:
Given :
- The points (a, 0) , (0 , b) & (1, 1) are collinear.
To Prove :
- 1/a + 1/b = 1
Proof :
Given that, The points (a, 0) , (0 , b) & (1, 1) are collinear.
.°. Area of triangle formed by these points is equal to 0.
=> ¹/2 [x¹(y² - y³) + x²(y³ - y¹) + x³(y¹ - y²)] = 0
Given that, Points are (a, 0) , (0 , b) & (1, 1).
Where,
- (x¹ , y¹) = (a, 0)
- (x² , y²) = (0 , b)
- (x³ , y³) = (1 , 1)
Substitute all values in above formula,
=> ¹/2 [a(b - 1) + 0(1 - 0) + 1(0 - b)] = 0
=> ¹/2 [ab - a - b] = 0
=> ab - a - b = 0 × 1/2
=> ab - a - b = 0
=> -(a + b) = -ab
=> a + b = ab
Divide by ab on both sides,
=> a/ab + b/ab = ab/ab
=> 1/b + 1/a = 1
=> 1/a + 1/b = 1
- Hence Proved!!
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