if the points (a 0) (0 b) and (3 2) are collinear prove that 1/a+1/b=1
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Step-by-step explanation:
We know that,
Three points are collinear
Then,
Area of triangle =0
1/2 [ X1(y2-y3) + X3(y3 - y1) + X3(X1 - X2)]
= [ a(b-2) + 0(0-2) + 3 (a-0)]
= ab - 2a +3a = 0
ab+ a= 0
a(b+1) = 0
a= 0 , b= -1
1/a + 1/b = 1 [ by substituting values of a and b ]
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