Question

if the points (a,1),(2,-3) are conjugate w.r.t x²+y²+4x-6y-12=0 then [a]=​

Answer 1

Step-by-step explanation:

Given points are conjugate

∴S12=0

x1x2+y1y2+2(x+x1)−3(y+y1)−12=0

2a−3+2(a+2)−3(1−3)−12=0

2a−3+2a+4+6−12=0

4a−5=0

a=5/4=1.25

[a]=[1.25]=1