If the points A(1,-2) B(2,3) C(x,2) D(-4,-3) form a parallelogram. Find x and also the height of the parallelogram by taking AB as the base
Answers
Answered by
1
Heya !!!
A(1,-2) , B(2,3) , C(X,2) and D(-4,-3) be the vertices of a parallelogram ABCD . Join AC and BD , Intersecting each other at the point Of.
We know that the diagonals of parallelogram bisect eaach other.
Therefore,
O is the midpoint of AC as well as BD.
Therefore,
A (1,-2) and C (X,2)
Here,
X1 = 1 , Y1 = -2 and X2 = X , Y2 = 2
Midpoint of AC is ( X1+X2/2 , Y1+Y2/2) => ( 1+X/2 , -2 + 2/2 ) => ( 1+X/2 , 0/2)
And,
B(2,3) and D(-4,-3)
Here,
X1 = 2 , Y1 = -4 and X2 = -4 , Y2 = -3
Midpoint of BD is ( X1+X2/2 , Y1+Y2/2) => ( 2+(-4)/2 , ( -4 + (-3) /2 )
=> ( 2 -4/2 , -4 -3 /2)
=> ( -2/2 , -7/2) = ( -1 , -7/2)
Therefore,
( 1+X/2) = -1
1+ X = -2
X = -2 -1
X = -3
HOPE IT WILL HELP YOU..... :-)
A(1,-2) , B(2,3) , C(X,2) and D(-4,-3) be the vertices of a parallelogram ABCD . Join AC and BD , Intersecting each other at the point Of.
We know that the diagonals of parallelogram bisect eaach other.
Therefore,
O is the midpoint of AC as well as BD.
Therefore,
A (1,-2) and C (X,2)
Here,
X1 = 1 , Y1 = -2 and X2 = X , Y2 = 2
Midpoint of AC is ( X1+X2/2 , Y1+Y2/2) => ( 1+X/2 , -2 + 2/2 ) => ( 1+X/2 , 0/2)
And,
B(2,3) and D(-4,-3)
Here,
X1 = 2 , Y1 = -4 and X2 = -4 , Y2 = -3
Midpoint of BD is ( X1+X2/2 , Y1+Y2/2) => ( 2+(-4)/2 , ( -4 + (-3) /2 )
=> ( 2 -4/2 , -4 -3 /2)
=> ( -2/2 , -7/2) = ( -1 , -7/2)
Therefore,
( 1+X/2) = -1
1+ X = -2
X = -2 -1
X = -3
HOPE IT WILL HELP YOU..... :-)
Similar questions