if the points A(2, 1, 1), B(0 ,-1 ,4)& C(k ,3 ,-2) are colinear, then k=
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A, B and C are colinear
Determinants of points A,B and C = 0.
det( 2, 1 , 1 ), (0, -1 , 4), (k , 3 ,-2) =0
2(8-12) -1(0-4k)+1(0+4k)=0
16 - 24 + 4k + 4k = 0
8k - 8 = 0
8k = 8
k = 1
Hope This Helps You!
Determinants of points A,B and C = 0.
det( 2, 1 , 1 ), (0, -1 , 4), (k , 3 ,-2) =0
2(8-12) -1(0-4k)+1(0+4k)=0
16 - 24 + 4k + 4k = 0
8k - 8 = 0
8k = 8
k = 1
Hope This Helps You!
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