Question

If the points A(-2, -1), B(1, 0), C(p, 3) and D(1,q) form a parallelogram ABCD, find the values of p and q.

Answer 1

Answer:

p = 4 and q = 2

Step-by-step explanation:

The diagonals of the parallelogram bisect each other.

This means the mid-point of the diagonal AC coincides with the mid-point of the diagonal BD.

Mid-point of AC = $(\frac{p-2}{2}, \frac{3-1}{2} ) = (\frac{p-2}{2}, 1} )$

Mid-point of BD = $(\frac{2}{2} , \frac{q+0}{2} ) = (1, \frac{q}{2} )$

Since mid-point of AC = mid-point of BD,

$\frac{p-2}{2} = 1$ and $\frac{q}{2} = 1$

p - 2 = 2 and q = 2

p = 2 + 2 = 4 and q = 2

Hence, p = 4 and q = 2.

Answer 2

here's ur answer mate....................