If the points a(2, 1), b(a, b) and c(4, 1) are collinear and a b = 1, find the values of a and b respectively.
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here is your correct answer
area of triangle =
½[a1(b2-b3)+a2(b3-b1)+a3(b1-b2)
as points are collinear the area is zero here
a1=-2. b1=1
a2=a. b2=b
a3=4. b3=1
so putting value in eq
a=1 b=1
area of triangle =
½[a1(b2-b3)+a2(b3-b1)+a3(b1-b2)
as points are collinear the area is zero here
a1=-2. b1=1
a2=a. b2=b
a3=4. b3=1
so putting value in eq
a=1 b=1
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