if the points a(3,5) and b(1,4) lie on the graph of the line ax + by=7. therefore, x=3,y=5 and x=1,y=4 are solutions of the equation ax+by=7
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Answered by
392
If (3,5) lies on the line ax+by=7.
Then x=3,y=5,
a(3)+b(5)=7
3a+5b=7
5b=7-3a
b=7/5-3a/5 ---------- 1
If (1,4) lies on the line
ax+by=7.
Then
x=1,y=4,
a(1)+b(4)=7
a+4b=7
substitute the value of b in the equation.
a+4(7/5-3a/5) =7
a+(28/5-12a/5)=7
a-12a/5=7-28/5
5a/5-12a/5=35/5-28/5
-7a/5=7/5
-7a=7
a=-1
substitute the value of a in equation--1
b=7/5-3(-1)/5
b=7/5-(-3/5)
b=7/5+3/5
b=10/5
b=2
therefore,a=-1,b=2
Then x=3,y=5,
a(3)+b(5)=7
3a+5b=7
5b=7-3a
b=7/5-3a/5 ---------- 1
If (1,4) lies on the line
ax+by=7.
Then
x=1,y=4,
a(1)+b(4)=7
a+4b=7
substitute the value of b in the equation.
a+4(7/5-3a/5) =7
a+(28/5-12a/5)=7
a-12a/5=7-28/5
5a/5-12a/5=35/5-28/5
-7a/5=7/5
-7a=7
a=-1
substitute the value of a in equation--1
b=7/5-3(-1)/5
b=7/5-(-3/5)
b=7/5+3/5
b=10/5
b=2
therefore,a=-1,b=2
Answered by
78
Answer:
a=-1
b=2
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