if the points a(4,3)and b(2,y) are lie on the circle with center o(2,3) find y
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Answered by
2
r=√(4-2)^2 +(3-3)^2
=2
therefore
(2-2)^2+(y-3)^2=2^2
solving this we get
y=1;5
=2
therefore
(2-2)^2+(y-3)^2=2^2
solving this we get
y=1;5
Answered by
1
Answer:
OA= RADIUS=√(4-2)^2 +(3-3)^2
=2
OB =OA as it is also the radius
therefore
(2-2)^2+(y-3)^2=2^2
solving this we get
y=1;5
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