Question

If the points A (4,3) and B (x,5) are on the circle with centre O(2,3) then find the value of x.​

Answer 1

Answer:

Since, AO=BO= radius of circle

√(2-4)^2+(3-3)^2= √(2-x)^2+(3-5)^2

squaring on both sides, we get

(2-4)^2+(3-3)^2= (2-x)^2+(3-5)^2

4+0=4+x^2-4x+4

x^2-4x+4=0

x^2-2x-2x+4=0

x(x-2)-2(x-2)=0

(x-2)(x-2)=0

therefore, x=2

Answer 2

Answer:

x=2

Step-by-step explanation:

Since, A and B lie in the circle having centre O.

OA=OB

√(4-2)²+(3-3)²=√(x-2)²+(5-3)²

2=√(x-2)²+4

4=(x-2)²+4

(x-2)²=0

x=2