if the points A(6,1 ) B(8,2) C(9,4) and D(p,3) are the vertices of a parallelogram taken in order. find the value of p
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Given that ABCD is a parallelogram.
Let co-ordinate A be the (x1,y1), B be the (x2,y2), C be the (x3,y3) and D be the (x4,y4).
We know that diagonals of the parallelogram bisects each other.
So, Mid - point of AC = Mid - point of BD
Mid-point of AC = x1 + x3/2 , y1 + y3/2
= 6 + 9/2 , 1 + 4/2
= 15/2 , 5/2
Mid-point of BD = x2 + x4/2 , y2 + y4/2
= 8 + p/2 , 2 + 3/2
= 8 + p/2 , 5/2
8 + p/2 = 15/2
8 + p = 15
p = 15 - 8
p = 7
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