If the points A(6, 1), B(8, 2), C(9, 4) and D(p, 3) taken in order are the vertices of a parallelogram, find the value of p using distance formula.
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Distance of AB=square root of (8-6)^2 +(2-1)^2
=squr root of 5 (mark it as equation 1)
Distance of CD=squr root of (p-9)^2 + (3-4)^2
=(p-9)+1 (equation 2)
since given that taken in order of vertices of a parallelogram,
distance of AB= distance of CD
by equating the values in the above equation
the p=8squr root of 5
=squr root of 5 (mark it as equation 1)
Distance of CD=squr root of (p-9)^2 + (3-4)^2
=(p-9)+1 (equation 2)
since given that taken in order of vertices of a parallelogram,
distance of AB= distance of CD
by equating the values in the above equation
the p=8squr root of 5
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