If the points A(6, 1), B(8, 2), C(9, 4) and D(p, 3) taken in order are the vertices of a parallelogram, find the value of p using distance formula
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the distance between A and B is √(6-8)²+(1-2)²=√4-1=√3units.
as it is a paralleogram AB=CD
⇒CD=√3
⇒√(9-p)²+(4-3)²=√3
⇒(9-p)²+1=3
⇒(9-p)=2
⇒p=7
as it is a paralleogram AB=CD
⇒CD=√3
⇒√(9-p)²+(4-3)²=√3
⇒(9-p)²+1=3
⇒(9-p)=2
⇒p=7
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