Question

if the points A 6, 18, 29, 4 and DP, 3 are the vertices of a parallelogram taken order find the value of p​

Answer 1

A(6,8)=(x1,y1) , D=(p,3)=(x2,y2)

d(AD)=√(x2-x1)^2+(y2-y1)^2

=√(p-6)^2+(3-8)^2

=√(p-6)^2+(-5)^2

=√p^2-6*2*p+36+25

=√p^2-12p+61