If the points A, B, C collinear then a) |AB ACI= BC c) slope of BC = slope of CA b) ar( AABC ) = 0 d) slope of AB = slope of BC -
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Step-by-step explanation:
i) Slope of AB=5−412−8=14=4
Slope of BC=9−528−12=416=4
Hence AB∣∣BC, but B is a point of intersect.
Hence A, B, C are collinear.
(ii) Slope of AB=3−16−6+18=−1312=−1312
Slope of BC=−10−36+6=−1312=−1312
Slope of AB= slope of BC
Hence A, B, C are collinear.
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Step-by-step explanation:
(i) Slope of AB=
5−4
12−8
=
1
4
=4
Slope of BC=
9−5
28−12
=
4
16
=4
Hence AB∣∣BC, but B is a point of intersect.
Hence A, B, C are collinear.
(ii) Slope of AB=
3−16
−6+18
=
−13
12
=−
13
12
Slope of BC=
−10−3
6+6
=
−13
12
=−
13
12
Slope of AB= slope of BC
Hence A, B, C are collinear
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