If the points A(k + 1, 2k), B(3k, 2k + 3) and C(5k - 1, 5k) are collinear, then find the value of k.
Answers
Answered by
14
Answer:
Points A, B and C are collinear.
Therefore,
½ [(k + 1)(2k + 3 – 5k) + 3k(5k – 2k) + (5k – 1)(2k – 2k – 3)] = 0
(k + 1)(3 – 3k) + 9k2 – 3(5k – 1) = 0
2k2 – 5k + 2 = 0
(k – 2)(2k – 1) = 0
k = 2, 1/2
Answered by
0
Answer:
Points A, B and C are collinear. Therefore, ½ [(k + 1)(2k + 3 – 5k) + 3k(5k – 2k) + (5k – 1)(2k – 2k – 3)] = 0 (k + 1)(3 – 3k) + 9k2 – 3(5k – 1) = 0 2k2 – 5k + 2 = 0
Step-by-step explanation:
Similar questions